•  zhunk   ( @zhunk@beehaw.org ) 
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      1 year ago

      For a geostationary orbit, which is where the center of mass of a space elevator would be:

      h = ³√ G * m * T² / ( 4 * π² ) - r

      • h: orbit height (m)
      • G: gravitational constant
      • m: mass of celestial body (kg)
      • T: period of rotation (s)
      • r: radius of celestial body (m)

      So, if the mass goes way up, the height of the orbit will, too, unless something crazy happens like the planet spinning super fast.