SnokenKeekaGuard ( SnokenKeekaGuard@lemmy.dbzer0.com ) M to Anti Meme@sopuli.xyz · 1 year agoHowwww??lemmy.dbzer0.comimagemessage-square24linkfedilinkarrow-up171
arrow-up171imageHowwww??lemmy.dbzer0.comSnokenKeekaGuard ( SnokenKeekaGuard@lemmy.dbzer0.com ) M to Anti Meme@sopuli.xyz · 1 year agomessage-square24linkfedilink
minus-squareBCsven ( BCsven@lemmy.ca ) linkfedilinkarrow-up18·1 year agoMaybe thee is an elegant way but X+y+w+z=360° Given X+y=w+z Therefore we can sub X+y with w+z (W+z)+(w+z)=360° 2(W+z)=360° Divide both sides by 2 W+z=360°/2 W+z=180° Straight lines are defined as having/being 180 angle
minus-squareSnokenKeekaGuard ( SnokenKeekaGuard@lemmy.dbzer0.com ) OPlinkfedilinkarrow-up7·1 year agoOh i forgot about x+y being given as w+z. Yep with that its all good. I thought you made that assumption.
minus-squareHeuristicAlgorithm9 ( HeurtisticAlgorithm9@feddit.uk ) linkfedilinkarrow-up3·1 year agoThe elegant way would be to use radians over degrees
minus-squareBCsven ( BCsven@lemmy.ca ) linkfedilinkarrow-up3·1 year agoYou have to show your work in snokenkeekaguard’s class
minus-squareHeuristicAlgorithm9 ( HeurtisticAlgorithm9@feddit.uk ) linkfedilinkarrow-up1·1 year agoWdym?
Maybe thee is an elegant way but
X+y+w+z=360°
Given X+y=w+z
Therefore we can sub X+y with w+z
(W+z)+(w+z)=360°
2(W+z)=360°
Divide both sides by 2
W+z=360°/2
W+z=180°
Straight lines are defined as having/being 180 angle
Oh i forgot about x+y being given as w+z. Yep with that its all good. I thought you made that assumption.
The elegant way would be to use radians over degrees
You have to show your work in snokenkeekaguard’s class
Wdym?