Sorry if this is a dumb question but some communities show up here and some 404. How do I get a community to show up in the list that hasn’t synced yet. Example !requests@lemmit.online

I checked the faq and don’t see this answer there.

  •  ffmike   ( @ffmike@beehaw.org ) 
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    1 year ago
    1. Go to the Communities page
    2. Put part of the name (“requests” works in this case) in the search box
    3. Click the Search button

    If the community you’re looking for doesn’t show up, wait a few minutes and try again. It’s not at all evident from the UI, but some part of the search process is a background process. So it will eventually show up (and indeed, the one you’re looking for is there now).

    If it still doesn’t show on the list in 5-10 minutes, try broadening your search to the URL of the original community. I haven’t checked the code, but this may be necessary if no one from Beehaw has been into the community you’re looking for:

    1. Switch the search type from “Communities” to “All”
    2. Search for the full URL of the community on its home site (something like https://programming.dev/c/code_golf , not the ! form)
  •  Wilshire   ( @Wilshire@beehaw.org ) 
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    1 year ago

    It’s synced now, so you should be able to find it by searching ‘requests’ in the community tab. It won’t show up with the full name if it’s already been synced. That might have be why.

  • I found this bookmarklet somewhere else, and it’s super handy. You simply click the bookmark when you are on the lemmy community page, and it’ll send you to a beehaw page where you can subscribe to it directly:

    javascript:(function() { const home = 'beehaw.org'; /*replace this with your local instance's host name */ const url = window.location.href; let community = url.split('/c/')[1]; if( !community.includes('@') ) { community += '@' + url.split('/')[2]; } if( community.endsWith( '@' + home ) ) { community = community.substring(0, community.length - 1 - home.length); } window.location.href = 'https://' + home + '/c/' + community; })();