- jerkface ( @jerkface@lemmy.ca ) English2•51 minutes ago
Doesn’t this also imply that
i == 1
becauseCB
has zero length, forcingAC
andAB
to be coincident? That sounds like a disproving contradiction to me. - BorgDrone ( @BorgDrone@lemmy.one ) English7•3 hours ago
Now calculate the angles
- Rivalarrival ( @Rivalarrival@lemmy.today ) English4•2 hours ago
That’s actually pretty easy. With CB being 0, C and B are the same point. Angle A, then, is 0, and the other two angles are undefined.
No thank you
- blackbrook ( @blackbrook@mander.xyz ) English10•3 hours ago
You need to add some disclaimer to this diagram like “not to scale”…
It’s to scale.
Which scale is left as an exercise to the reader.
- jerkface ( @jerkface@lemmy.ca ) English2•56 minutes ago
I really don’t think it is.
- barsoap ( @barsoap@lemm.ee ) English1•3 hours ago
Looks like a finite state machine or some other graph to me, which just happens to have no directed edges.
- Boomkop3 ( @Boomkop3@reddthat.com ) English1•3 hours ago
Turn around…
- Maiq ( @Maiq@lemy.lol ) English1•1 hour ago
Bright eyes.
- puchaczyk ( @puchaczyk@lemmy.blahaj.zone ) English15•7 hours ago
This is why a length of a vector on a complex plane is |z|=√(z×z). z is a complex conjugate of z.
- Dr. Bluefall ( @drbluefall@toast.ooo ) English2•2 hours ago
[ you may want to escape the characters in your comment… ]
- randy ( @randy@lemmy.ca ) English1•2 hours ago
I’ve noticed that, if an equation calls for a number squared, they usually really mean a number multiplied by its complex conjugate.
- ShinkanTrain ( @ShinkanTrain@lemmy.ml ) English6•7 hours ago
- produnis ( @produnis@discuss.tchncs.de ) English6•8 hours ago
Too complexe for me ;)
- ornery_chemist ( @ornery_chemist@mander.xyz ) English12•9 hours ago
Isn’t the squaring actually multiplication by the complex conjugate when working in the complex plane? i.e., √((1 - 0 i) (1 + 0 i) + (0 - i) (0 + i)) = √(1 + - i2) = √(1 + 1) = √2. I could be totally off base here and could be confusing with something else…
- diaphanous ( @diaphanous@feddit.org ) English6•8 hours ago
I think you’re thinking of taking the absolute value squared, |z|^2 = z z*
- Boomkop3 ( @Boomkop3@reddthat.com ) English2•3 hours ago
Turn around…
- Rivalarrival ( @Rivalarrival@lemmy.today ) English1•1 hour ago
Every now and then, I get a little bit lonely and you’re never coming 'round
- Boomkop3 ( @Boomkop3@reddthat.com ) English1•3 hours ago
Exactly what I thought of, but then I was like… nah that’s too cheesy
Too cheesy?!
- Stomata ( @Stomata@buddyverse.one ) English2•8 hours ago
Stop daydreaming 😁
- I_am_10_squirrels ( @I_am_10_squirrels@beehaw.org ) English5•11 hours ago
The length would be equal to the absolute value